What is the best way to render PartialView to a Layout Page in MVC?

Question

There is a layout page in my MVC5 project and I want to render all the page contents (partial views) by clicking menu links (hyperlink) on the left side as show

Answer 1

You have to first wrap your body content in div and assign any id to it:

@RenderBody()

Now in Script Menu click event:

$(".menuLinkItem").click(function (e) {
    e.preventDefault();        
    var controllerName = $(this).attr('data-controllername');
    var actionName = $(this).attr('data-actionname'); 

    if (String(actionName).trim() == '') {
        return false;
    }
    if (typeof (controllerName) == "undefined") {
        return false;
    }

    var url = "/" + controllerName + "/" + actionName;

    //Open url in new tab with ctrl key press
    if (e.ctrlKey) {
        window.open(url, '_blank');
        event.stopPropagation();
        return false;
    }            

    $.ajax({
        url: url,
        type: 'POST',
        success: function (data) {
            var requestedUrl = String(this.url).replace(/[&?]X-Requested-With=XMLHttpRequest/i, "");
            if (typeof (requestedUrl) == "undefined" || requestedUrl == 'undefined') {
                requestedUrl = window.location.href;
            }

            // if the url is the same, replace the state
            if (typeof (history.pushState) != "undefined") {
                if (window.location.href == requestedUrl) {
                    history.replaceState({ html: '' }, document.title, requestedUrl);
                }
                else {
                    history.pushState({ html: '' }, document.title, requestedUrl);
                }
            }

            $("#divContentArea").html(data);                

        },
        error: function (xhr) {
        }
    });

});

Controller:

[AcceptVerbs(HttpVerbs.Get | HttpVerbs.Post)]
public PartialViewResult Index()
{
        if (HttpContext.Request.HttpMethod == "GET")
        {
            return View();
        }
        else
        {
            return PartialView();
        }
}