How to convert []int8 to string

Question

What\'s the best way (fastest performance) to convert from []int8 to string?

For []byte we could do string(byteslice), but for

Answer 1

Not entirely sure it is the fastest, but I haven't found anything better. Change ba := []byte{} for ba := make([]byte,0, len(bs) so at the end you have:

func B2S(bs []int8) string {
    ba := make([]byte,0, len(bs))
    for _, b := range bs {
        ba = append(ba, byte(b))
    }
    return string(ba)
}

This way the append function will never try to insert more data that it can fit in the slice's underlying array and you will avoid unnecessary copying to a bigger array.