Make Call in Android Application using default call application

Question

I am using following code to make a call from my android application:

Intent intent = new Intent(Intent.ACTION_CALL);                 
intent.setData(Uri.par         


        

Answer 1

find all app with dial ability

fun getPackagesOfDialerApps(context: Context): List {
    val packageNames = ArrayList()
    // Declare action which target application listen to initiate phone call
    val intent = Intent()
    intent.action = Intent.ACTION_DIAL
    // Query for all those applications
    val resolveInfos = context.packageManager.queryIntentActivities(intent, 0)
    // Read package name of all those applications
    for (resolveInfo in resolveInfos) {
        val activityInfo = resolveInfo.activityInfo
        packageNames.add(activityInfo.applicationInfo.packageName)
    }
    return packageNames
}

call method

val callIntent = Intent(Intent.ACTION_DIAL, Uri.parse("tel:02188888888"))
callIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
context?.let {
    for(dialerApp in Utils.getPackagesOfDialerApps(it)){
        val appPackageName= dialerApp.toLowerCase(Locale.ENGLISH)
        if(appPackageName == "com.android.phone" ||
            appPackageName  == "com.android.server.telecom" ||
            appPackageName == "com.samsung.android.contacts"){
            callIntent.setPackage(appPackageName)
            break
        }
    }
}
try {
    startActivity(callIntent)
} catch (ex: ActivityNotFoundException){
    callIntent.setPackage(null)
    startActivity(callIntent)
}