Mongodb find a document with all subdocuments satisfying a condition

Question

I have Game collection in my DB:

var game = {
  players: [{username:\"user1\", status:\"played\"},
            {username:\"user2\", status:\"accepted\"}]
}
<         


        

Answer 1

I ran into this problem too. I was trying to use $all and making little to no progress. It helped to flip my perspective on the problem and use $not instead. I wrote about what I found here.

In your situation, you should be able to do something like this:

db.games.find({
  players: {
    $not: {
      $elemMatch: {
        status: { $ne: "played" }
      }
    }
  }
})

Find all documents with a player status not equal to "played" and return the inverse of that set. The nice thing about this is that you never have to worry about adding more status values.