I have 2 dates, say 28-Mar-2011 and 29-Jun-2011. I need an sql query that will display the months between these 2 dates including the months containing the dates, ie. June,
declare
v_date_from_first_day date;
v_date_to_last_day date;
v_month_name varchar2(10);
v_month_number number;
v_year_number number;
v_month_diff number;
begin
v_date_to_last_day := to_date('31.12.2018');
v_date_from_first_day := to_date('01.01.2018');
select months_between(v_date_to_last_day,v_date_from_first_day) as diff into v_month_diff from dual;
for i in 1..round(v_month_diff, 2) loop
select
to_char(trunc(add_months(v_date_to_last_day - months_between(v_date_from_first_day, v_date_to_last_day), -i)), 'fmMonth') as month_nm,
to_char(trunc(add_months(v_date_to_last_day - months_between(v_date_from_first_day, v_date_to_last_day), -i)), 'MM') as month_num,
to_char(trunc(add_months(v_date_to_last_day - months_between(v_date_from_first_day, v_date_to_last_day), -i)), 'YYYY') as year_num
into v_month_name, v_month_number, v_year_number
from dual;
dbms_output.put_line(v_month_number || '/' || v_year_number);
dbms_output.put_line(v_month_name || '/' || v_year_number);
end loop;
end;
Output:
12/2018
11/2018
10/2018
9/2018
8/2018
7/2018
6/2018
5/2018
4/2018
3/2018
2/2018
1/2018
Here, month names are in Croatian
Prosinac/2018
Studeni/2018
Listopad/2018
Rujan/2018
Kolovoz/2018
Srpanj/2018
Lipanj/2018
Svibanj/2018
Travanj/2018
Ožujak/2018
Veljača/2018
Siječanj/2018