XSLT 1.0 Get Current DateTime

Question

I have a node in my XML file containing the following:

2011-12-01T16:33:33Z

I wish to take this line and replace it w

Answer 1

Playing with DateTime is not possible with XSLT 1.0 alone .. In a similar situations I took help of scripting .. (C#)

Sample XML:

  2011-12-01T16:33:33Z

Sample XSLT:

Resulting Output:

  2012-02-22T18:03:12Z

The script may reside in a same file (like I have it in my sample XSLT code) or if the code triggering XSLTransformation is C# then move the same code in the calling place :)