Swift: second occurrence with indexOf

Question

let numbers = [1,3,4,5,5,9,0,1]

To find the first 5, use:

numbers.indexOf(5)

How do I find the secon

Answer 1

I don't think you can do it with indexOf. Instead you'll have to use a for-loop. A shorthand version:

let numbers = [1,3,4,5,5,9,0,1]
var indexes = [Int]()
numbers.enumerate().forEach { if $0.element == 5 { indexes += [$0.index] } }

print(indexes) // [3, 4]