Truncate a decimal value in C++

Question

What\'s the easiest way to truncate a C++ float variable that has a value of 0.6000002 to a value of 0.6000 and store it back in the variable?

Answer 1

Similar to other answers, BUT you must not forget that round, floor and trunc are different by definition. See the definition and output example of the following:

http://www.cplusplus.com/reference/cmath/trunc/

In this case we need to trucate with a precision of 4 decimals and get rid of non-significant decimals:

trunc(valueToTrunc*10000)/10000

or

value = (double)((int)(valueToTrunc*10000))/(double)10000