How does reduce function work in python3 with three parameters instead of two. So, for two,
reduce
tup = (1,2,3) reduce(lambda x, y: x+y, tup) <
tup = (1,2,3) reduce(lambda x, y: x+y, tup)
reduce optional third argument :
>>> import functools >>> test = [] >>> functools.reduce((lambda x,y: x+y), test, "testing")