'strcpy' with 'malloc'?

Question

Is it safe to do something like the following?

#include 
#include 
#include 

int main(void)
{
    char* msg;
         


        

Answer 1

 char* msg;
 strcpy(msg, "Hello World!!!");  //<---------Ewwwww
 printf("%s\n", msg); 

This is UB. No second thoughts. msg is a wild pointer and trying to dereference it might cause segfault on your implementation.

msg to be pointing to a valid memory location large enough to hold "Hello World".

Try

char* msg = malloc(15);
strcpy(msg, "Hello World!!!");

or

char msg[20]; 
strcpy(msg, "Hello World!!!");