How do you read a file inside a zip file as text, not bytes?

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我寻月下人不归
我寻月下人不归 2020-12-09 02:03

A simple program for reading a CSV file inside a zip file works in Python 2.7, but not in Python 3.2

$ cat test_zip_file_py3k.py 
import csv, sys, zipfile

z         


        
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  •  时光说笑
    2020-12-09 02:09

    I just noticed that Lennart's answer didn't work with Python 3.1, but it does work with Python 3.2. They've enhanced zipfile.ZipExtFile in Python 3.2 (see release notes). These changes appear to make zipfile.ZipExtFile work nicely with io.TextWrapper.

    Incidentally, it works in Python 3.1, if you uncomment the hacky lines below to monkey-patch zipfile.ZipExtFile, not that I would recommend this sort of hackery. I include it only to illustrate the essence of what was done in Python 3.2 to make things work nicely.

    $ cat test_zip_file_py3k.py 
    import csv, io, sys, zipfile
    
    zip_file    = zipfile.ZipFile(sys.argv[1])
    items_file  = zip_file.open('items.csv', 'rU')
    # items_file.readable = lambda: True
    # items_file.writable = lambda: False
    # items_file.seekable = lambda: False
    # items_file.read1 = items_file.read
    items_file  = io.TextIOWrapper(items_file)
    
    for idx, row in enumerate(csv.DictReader(items_file)):
        print('Processing row {0} -- row = {1}'.format(idx, row))
    

    If I had to support py3k < 3.2, then I would go with the solution in my other answer.

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