“synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.” problem in TensorFlow

Question

I installed TensorFlow 1.10.1 but when I tried to import TensorFlow it said that I need TensorFlow version 1.10.0. Thus, I installed it and now I get the following warnings:

Answer 1

The newest numpy release notes (1.17) has:

Future Changes

Shape-1 fields in dtypes won’t be collapsed to scalars in a future version
Currently, a field specified as [(name, dtype, 1)] or "1type" is interpreted 
as a scalar field (i.e., the same as [(name, dtype)] or [(name, dtype, ()]). 
This now raises a FutureWarning; in a future version, it will be interpreted 
as a shape-(1,) field, i.e. the same as [(name, dtype, (1,))] or "(1,)type" 
(consistently with [(name, dtype, n)] / "ntype" with n>1, which is already 
equivalent to [(name, dtype, (n,)] / "(n,)type").

https://docs.scipy.org/doc/numpy/release.html

Thus with your expression:

In [123]: np.dtype([("qint8", np.int8, 1)])                                                                  
/usr/local/bin/ipython3:1: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  #!/usr/bin/python3
Out[123]: dtype([('qint8', 'i1')])

In [124]: np.dtype([("qint8", np.int8, (1,))])                                                               
Out[124]: dtype([('qint8', 'i1', (1,))])

In [125]: np.dtype([("qint8", np.int8)])                                                                     
Out[125]: dtype([('qint8', 'i1')])

In [126]: np.dtype([("qint8", np.int8, 2)])                                                                  
Out[126]: dtype([('qint8', 'i1', (2,))])

In [127]: np.__version__                                                                                     
Out[127]: '1.17.0'