How to compare two decimal numbers in bash/awk?

Question

I am trying to compare two decimal values but I am getting errors. I used

if [ \"$(echo $result1 \'>\' $result2 | bc -l)\" -eq 1 ];then

Answer 1

You can do it using Bash's numeric context:

if (( $(echo "$result1 > $result2" | bc -l) )); then

bc will output 0 or 1 and the (( )) will interpret them as false or true respectively.

The same thing using AWK:

if (( $(echo "$result1 $result2" | awk '{print ($1 > $2)}') )); then