I have the following date: 2011-08-12T20:17:46.384Z
. What format is this? I\'m trying to parse it with Java 1.4 via DateFormat.getDateInstance().parse(
@John-Skeet gave me the clue to fix my own issue around this. As a younger programmer this small issue is easy to miss and hard to diagnose. So Im sharing it in the hopes it will help someone.
My issue was that I wanted to parse the following string contraining a time stamp from a JSON I have no influence over and put it in more useful variables. But I kept getting errors.
So given the following (pay attention to the string parameter inside ofPattern();
String str = "20190927T182730.000Z"
LocalDateTime fin;
fin = LocalDateTime.parse( str, DateTimeFormatter.ofPattern("yyyyMMdd'T'HHmmss.SSSZ") );
Error:
Exception in thread "main" java.time.format.DateTimeParseException: Text
'20190927T182730.000Z' could not be parsed at index 19
The problem? The Z at the end of the Pattern needs to be wrapped in 'Z' just like the 'T' is. Change
"yyyyMMdd'T'HHmmss.SSSZ"
to "yyyyMMdd'T'HHmmss.SSS'Z'"
and it works.
Removing the Z from the pattern alltogether also led to errors.
Frankly, I'd expect a Java class to have anticipated this.