How do I create a GUID in Python that is platform independent? I hear there is a method using ActivePython on Windows but it\'s Windows only because it uses COM. Is there a
2019 Answer (for Windows):
If you want a permanent UUID that identifies a machine uniquely on Windows, you can use this trick: (Copied from my answer at https://stackoverflow.com/a/58416992/8874388).
from typing import Optional
import re
import subprocess
import uuid
def get_windows_uuid() -> Optional[uuid.UUID]:
try:
# Ask Windows for the device's permanent UUID. Throws if command missing/fails.
txt = subprocess.check_output("wmic csproduct get uuid").decode()
# Attempt to extract the UUID from the command's result.
match = re.search(r"\bUUID\b[\s\r\n]+([^\s\r\n]+)", txt)
if match is not None:
txt = match.group(1)
if txt is not None:
# Remove the surrounding whitespace (newlines, space, etc)
# and useless dashes etc, by only keeping hex (0-9 A-F) chars.
txt = re.sub(r"[^0-9A-Fa-f]+", "", txt)
# Ensure we have exactly 32 characters (16 bytes).
if len(txt) == 32:
return uuid.UUID(txt)
except:
pass # Silence subprocess exception.
return None
print(get_windows_uuid())
Uses Windows API to get the computer's permanent UUID, then processes the string to ensure it's a valid UUID, and lastly returns a Python object (https://docs.python.org/3/library/uuid.html) which gives you convenient ways to use the data (such as 128-bit integer, hex string, etc).
Good luck!
PS: The subprocess call could probably be replaced with ctypes directly calling Windows kernel/DLLs. But for my purposes this function is all I need. It does strong validation and produces correct results.