Sha256 in Objective-C for iPhone

Question

When I use this code to create a sha256 of a string

unsigned char hashedChars[32];
NSString *inputString;
inputString = [NSString stringWithFormat:@\"hello\"         


        

Answer 1

Try this, it worked for me

1) To get a hash for plain text input

-(NSString*)sha256HashFor:(NSString*)input
{   
    const char* str = [input UTF8String];
    unsigned char result[CC_SHA256_DIGEST_LENGTH];
    CC_SHA256(str, strlen(str), result);

    NSMutableString *ret = [NSMutableString stringWithCapacity:CC_SHA256_DIGEST_LENGTH*2];
    for(int i = 0; i

2) To get hash for NSData as input

Note:- I have used NSData category, so the code is as follow

    - (NSString *)SHA256_HASH {
    //if (!self) return nil;

    unsigned char hash[CC_SHA256_DIGEST_LENGTH];
    if ( CC_SHA256([(NSData*)self bytes], [(NSData*)self length], hash) ) {
        NSData *sha2 = [NSData dataWithBytes:hash length:CC_SHA256_DIGEST_LENGTH]; 

        // description converts to hex but puts <> around it and spaces every 4 bytes
        NSString *hash = [sha2 description];
        hash = [hash stringByReplacingOccurrencesOfString:@" " withString:@""];
        hash = [hash stringByReplacingOccurrencesOfString:@"<" withString:@""];
        hash = [hash stringByReplacingOccurrencesOfString:@">" withString:@""];
        // hash is now a string with just the 40char hash value in it
        //NSLog(@"hash = %@",hash);

        // Format SHA256 fingerprint like
        // 00:00:00:00:00:00:00:00:00
        int keyLength=[hash length];
        NSString *formattedKey = @"";
        for (int i=0; i