Python Pandas : pivot table with aggfunc = count unique distinct

Question

df2 = pd.DataFrame({\'X\' : [\'X1\', \'X1\', \'X1\', \'X1\'], \'Y\' : [\'Y2\',\'Y1\',\'Y1\',\'Y1\'], \'Z\' : [\'Z3\',\'Z1\',\'Z1\',\'Z2\']})

    X   Y   Z
0  X1  Y2         


        

Answer 1

aggfunc=pd.Series.nunique will only count unique values for a series - in this case count the unique values for a column. But this doesn't quite reflect as an alternative to aggfunc='count'

For simple counting, it better to use aggfunc=pd.Series.count