Does C++11 allow vector?

Question

Container requirements have changed from C++03 to C++11. While C++03 had blanket requirements (e.g. copy constructibility and assignability for vector), C++11 defines fine-g

Answer 1

No, I believe the allocator requirements say that T can be a "non-const, non-reference object type".

You wouldn't be able to do much with a vector of constant objects. And a const vector would be almost the same anyway.

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Many years later this quick-and-dirty answer still seems to be attracting comments and votes. Not always up. :-)

So to add some proper references:

For the C++03 standard, which I have on paper, Table 31 in section [lib.allocator.requirements] says:

T, U any type

Not that any type actually worked.

So, the next standard, C++11, says in a close draft in [allocator.requirements] and now Table 27:

T, U, C any non-const, non-reference object type

which is extremely close to what I originally wrote above from memory. This is also what the question was about.

However, in C++14 (draft N4296) Table 27 now says:

T, U, C any non-const object type

Possibly because a reference perhaps isn't an object type after all?

And now in C++17 (draft N4659) it is Table 30 that says:

T, U, C any cv-unqualified object type (6.9)

So not only is const ruled out, but also volatile. Probably old news anyway, and just a clarification.

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Please also see Howard Hinnant's first-hand info, currently right below.