Check if a string contains a number

Question

Most of the questions I\'ve found are biased on the fact they\'re looking for letters in their numbers, whereas I\'m looking for numbers in what I\'d like to be a numberless

Answer 1

https://docs.python.org/2/library/re.html

You should better use regular expression. It's much faster.

import re

def f1(string):
    return any(i.isdigit() for i in string)


def f2(string):
    return re.search('\d', string)


# if you compile the regex string first, it's even faster
RE_D = re.compile('\d')
def f3(string):
    return RE_D.search(string)

# Output from iPython
# In [18]: %timeit  f1('assdfgag123')
# 1000000 loops, best of 3: 1.18 µs per loop

# In [19]: %timeit  f2('assdfgag123')
# 1000000 loops, best of 3: 923 ns per loop

# In [20]: %timeit  f3('assdfgag123')
# 1000000 loops, best of 3: 384 ns per loop