Understanding typedefs for function pointers in C

Question

I have always been a bit stumped when I read other peoples\' code which had typedefs for pointers to functions with arguments. I recall that it took me a while to get around

Answer 1

A very easy way to understand typedef of function pointer:

int add(int a, int b)
{
    return (a+b);
}

typedef int (*add_integer)(int, int); //declaration of function pointer

int main()
{
    add_integer addition = add; //typedef assigns a new variable i.e. "addition" to original function "add"
    int c = addition(11, 11);   //calling function via new variable
    printf("%d",c);
    return 0;
}