Sum the digits of a number

Question

If I want to find the sum of the digits of a number, i.e.:

• Input: 932
• Output: 14, which is (9 + 3 + 2)

Answer 1

def digitsum(n):
    result = 0
    for i in range(len(str(n))):
        result = result + int(str(n)[i:i+1])
    return(result)

"result" is initialized with 0.

Inside the for loop, the number(n) is converted into a string to be split with loop index(i) and get each digit. ---> str(n)[i:i+1]

This sliced digit is converted back to an integer ----> int(str(n)[i:i+1])

And hence added to result.