Rvalue Reference is Treated as an Lvalue?

Question

I posted this answer: https://stackoverflow.com/a/28459180/2642059 Which contains the following code:

void foo(string&& bar){
    string* temp = &         


        

Answer 1

Here in this case named rvalue references are lvalues, while if the input type is const named rvalue references then it will be rvalue, here is a simple example:

#include 
#include 

void foo(const std::string&& bar) { 
    std::string* temp = &bar; // compile error, can't get address
    std::cout << *temp << " @:" << temp << std::endl;
}

int main()
{
    foo("test");
    return 0;
}

Hope this is useful.