I have (in the past) written cross-platform (Windows/Unix) applications which, when started from the command line, handled a user-typed Ctrl-C combinat
The closest that I've come to a solution is the SendSignal 3rd party app. The author lists source code and an executable. I've verified that it works under 64-bit windows (running as a 32-bit program, killing another 32-bit program), but I've not figured out how to embed the code into a windows program (either 32-bit or 64-bit).
How it works:
After much digging around in the debugger I discovered that the entry point that actually does the behavior associated with a signal like ctrl-break is kernel32!CtrlRoutine. The function had the same prototype as ThreadProc, so it can be used with CreateRemoteThread directly, without having to inject code. However, that's not an exported symbol! It's at different addresses (and even has different names) on different versions of Windows. What to do?
Here is the solution I finally came up with. I install a console ctrl handler for my app, then generate a ctrl-break signal for my app. When my handler gets called, I look back at the top of the stack to find out the parameters passed to kernel32!BaseThreadStart. I grab the first param, which is the desired start address of the thread, which is the address of kernel32!CtrlRoutine. Then I return from my handler, indicating that I have handled the signal and my app should not be terminated. Back in the main thread, I wait until the address of kernel32!CtrlRoutine has been retrieved. Once I've got it, I create a remote thread in the target process with the discovered start address. This causes the ctrl handlers in the target process to be evaluated as if ctrl-break had been pressed!
The nice thing is that only the target process is affected, and any process (even a windowed process) can be targeted. One downside is that my little app can't be used in a batch file, since it will kill it when it sends the ctrl-break event in order to discover the address of kernel32!CtrlRoutine.
(Precede it with start
if running it in a batch file.)