Given the Python function:
def a_method(arg1, arg2):
pass
How can I extract the number and names of the arguments. I.e., given that I h
In CPython, the number of arguments is
a_method.func_code.co_argcount
and their names are in the beginning of
a_method.func_code.co_varnames
These are implementation details of CPython, so this probably does not work in other implementations of Python, such as IronPython and Jython.
One portable way to admit "pass-through" arguments is to define your function with the signature func(*args, **kwargs)
. This is used a lot in e.g. matplotlib, where the outer API layer passes lots of keyword arguments to the lower-level API.