I have been adding logs to the console to check the status of different variables without using the Firefox debugger.
However, in many places in which I add a
I have been looking at the answers all impressive. I think He should provide the code that is giving him a problem. Given the example below, If you have a script to link to jquery in page.php then you get that notice.
$().ready(function () {
$.ajax({url: "page.php",
type: 'GET',
success: function (result) {
$("#page").html(result);
}});
});