How to serialize a lambda?

Question

How can I elegantly serialize a lambda?

For example, the code below throws a NotSerializableException. How can I fix it without creating a Seriali

Answer 1

Very ugly cast. I prefer to define a Serializable extension to the functional interface I'm using

For example:

interface SerializableFunction extends Function, Serializable {}
interface SerializableConsumer extends Consumer, Serializable {}

then the method accepting the lambda can be defined as such :

private void someFunction(SerializableFunction function) {
   ...
}

and calling the function you can pass your lambda without any ugly cast:

someFunction(arg -> doXYZ(arg));