I\'ve run into a couple of cases now where it would be convenient to be able to find the \"topmost\" view controller (the one responsible for the current view), but haven\'t
This is an improvement to Eric's answer:
UIViewController *_topMostController(UIViewController *cont) {
UIViewController *topController = cont;
while (topController.presentedViewController) {
topController = topController.presentedViewController;
}
if ([topController isKindOfClass:[UINavigationController class]]) {
UIViewController *visible = ((UINavigationController *)topController).visibleViewController;
if (visible) {
topController = visible;
}
}
return (topController != cont ? topController : nil);
}
UIViewController *topMostController() {
UIViewController *topController = [UIApplication sharedApplication].keyWindow.rootViewController;
UIViewController *next = nil;
while ((next = _topMostController(topController)) != nil) {
topController = next;
}
return topController;
}
_topMostController(UIViewController *cont)
is a helper function.
Now all you need to do is call topMostController()
and the top most UIViewController should be returned!