I know how to use tee
to write the output (STDOUT
) of aaa.sh
to bbb.out
, while still displaying it in the terminal:
Like the accepted answer well explained by lhunath, you can use
command > >(tee -a stdout.log) 2> >(tee -a stderr.log >&2)
Beware than if you use bash you could have some issue.
Let me take the matthew-wilcoxson exemple.
And for those who "seeing is believing", a quick test:
(echo "Test Out";>&2 echo "Test Err") > >(tee stdout.log) 2> >(tee stderr.log >&2)
Personally, when I try, I have this result :
user@computer:~$ (echo "Test Out";>&2 echo "Test Err") > >(tee stdout.log) 2> >(tee stderr.log >&2)
user@computer:~$ Test Out
Test Err
Both message does not appear at the same level. Why Test Out
seem to be put like if it is my previous command ?
Prompt is on a blank line, let me think the process is not finished, and when I press Enter
this fix it.
When I check the content of the files, it is ok, redirection works.
Let take another test.
function outerr() {
echo "out" # stdout
echo >&2 "err" # stderr
}
user@computer:~$ outerr
out
err
user@computer:~$ outerr >/dev/null
err
user@computer:~$ outerr 2>/dev/null
out
Trying again the redirection, but with this function.
function test_redirect() {
fout="stdout.log"
ferr="stderr.log"
echo "$ outerr"
(outerr) > >(tee "$fout") 2> >(tee "$ferr" >&2)
echo "# $fout content :"
cat "$fout"
echo "# $ferr content :"
cat "$ferr"
}
Personally, I have this result :
user@computer:~$ test_redirect
$ outerr
# stdout.log content :
out
out
err
# stderr.log content :
err
user@computer:~$
No prompt on a blank line, but I don't see normal output, stdout.log content seem to be wrong, only stderr.log seem to be ok. If I relaunch it, output can be different...
So, why ?
Because, like explained here :
Beware that in bash, this command returns as soon as [first command] finishes, even if the tee commands are still executed (ksh and zsh do wait for the subprocesses)
So, if you use bash, prefer use the better exemple given in this other answer :
{ { outerr | tee "$fout"; } 2>&1 1>&3 | tee "$ferr"; } 3>&1 1>&2
It will fix the previous issues.
Now, the question is, how to retrieve exit status code ?
$?
does not works.
I have no found better solution than switch on pipefail with set -o pipefail
(set +o pipefail
to switch off) and use ${PIPESTATUS[0]}
like this
function outerr() {
echo "out"
echo >&2 "err"
return 11
}
function test_outerr() {
local - # To preserve set option
! [[ -o pipefail ]] && set -o pipefail; # Or use second part directly
local fout="stdout.log"
local ferr="stderr.log"
echo "$ outerr"
{ { outerr | tee "$fout"; } 2>&1 1>&3 | tee "$ferr"; } 3>&1 1>&2
# First save the status or it will be lost
local status="${PIPESTATUS[0]}" # Save first, the second is 0, perhaps tee status code.
echo "==="
echo "# $fout content :"
echo "<==="
cat "$fout"
echo "===>"
echo "# $ferr content :"
echo "<==="
cat "$ferr"
echo "===>"
if (( status > 0 )); then
echo "Fail $status > 0"
return "$status" # or whatever
fi
}
user@computer:~$ test_outerr
$ outerr
err
out
===
# stdout.log content :
<===
out
===>
# stderr.log content :
<===
err
===>
Fail 11 > 0