You can also use a list comprehension:
>>> newdict = {1:0, 2:0, 3:0}
>>> [k for k in newdict.keys()]
[1, 2, 3]
Or, shorter,
>>> [k for k in newdict]
[1, 2, 3]
Note: Order is not guaranteed on versions under 3.7 (ordering is still only an implementation detail with CPython 3.6).