Get path of executable

Question

I know this question has been asked before but I still haven\'t seen a satisfactory answer, or a definitive \"no, this cannot be done\", so I\'ll ask again!

All I wa

Answer 1

C++17, windows, unicode, using filesystem new api:

#include "..\Project.h"
#include 
using namespace std;
using namespace filesystem;

int wmain(int argc, wchar_t** argv)
{
    auto dir = weakly_canonical(path(argv[0])).parent_path();
    printf("%S", dir.c_str());
    return 0;
}

Suspect this solution should be portable, but don't know how unicode is implemented on other OS's.

weakly_canonical is needed only if you use as Output Directory upper folder references ('..') to simplify path. If you don't use it - remove it.

If you're operating from dynamic link library (.dll /.so), then you might not have argv, then you can consider following solution:

application.h:

#pragma once

//
// https://en.cppreference.com/w/User:D41D8CD98F/feature_testing_macros
//
#ifdef __cpp_lib_filesystem
#include 
#else
#include 

namespace std {
    namespace filesystem = experimental::filesystem;
}
#endif

std::filesystem::path getexepath();

application.cpp:

#include "application.h"
#ifdef _WIN32
#include     //GetModuleFileNameW
#else
#include 
#include      //readlink
#endif

std::filesystem::path getexepath()
{
#ifdef _WIN32
    wchar_t path[MAX_PATH] = { 0 };
    GetModuleFileNameW(NULL, path, MAX_PATH);
    return path;
#else
    char result[PATH_MAX];
    ssize_t count = readlink("/proc/self/exe", result, PATH_MAX);
    return std::string(result, (count > 0) ? count : 0);
#endif
}