Get path of executable

Question

I know this question has been asked before but I still haven\'t seen a satisfactory answer, or a definitive \"no, this cannot be done\", so I\'ll ask again!

All I wa

Answer 1

This way uses boost + argv. You mentioned this may not be cross platform because it may or may not include the executable name. Well the following code should work around that.

#include 

#include 

#include 

namespace fs = boost::filesystem;


int main(int argc,char** argv)
{
    fs::path full_path( fs::initial_path() );

    full_path = fs::system_complete( fs::path( argv[0] ) );

    std::cout << full_path << std::endl;

    //Without file name
    std::cout << full_path.stem() << std::endl;
    //std::cout << fs::basename(full_path) << std::endl;

    return 0;
}

The following code gets the current working directory which may do what you need

#include 
#include 

#include 

namespace fs = boost::filesystem;


int main(int argc,char** argv)
{
    //current working directory
    fs::path full_path( fs::current_path() );

    std::cout << full_path << std::endl;

    std::cout << full_path.stem() << std::endl;
    //std::cout << fs::basepath(full_path) << std::endl;

    return 0;
}

Note Just realized that basename() was deprecated so had to switch to .stem()