How to duplicate sys.stdout to a log file?

Question

Edit: Since it appears that there\'s either no solution, or I\'m doing something so non-standard that nobody knows - I\'ll revise my question to also ask: What is the best w

Answer 1

If you wish to log all output to a file AND output it to a text file then you can do the following. It's a bit hacky but it works:

import logging
debug = input("Debug or not")
if debug == "1":
    logging.basicConfig(level=logging.DEBUG, filename='./OUT.txt')
    old_print = print
    def print(string):
        old_print(string)
        logging.info(string)
print("OMG it works!")

EDIT: Note that this does not log errors unless you redirect sys.stderr to sys.stdout

EDIT2: A second issue is that you have to pass 1 argument unlike with the builtin function.

EDIT3: See the code before to write stdin and stdout to console and file with stderr only going to file

import logging, sys
debug = input("Debug or not")
if debug == "1":
    old_input = input
    sys.stderr.write = logging.info
    def input(string=""):
        string_in = old_input(string)
        logging.info("STRING IN " + string_in)
        return string_in
    logging.basicConfig(level=logging.DEBUG, filename='./OUT.txt')
    old_print = print
    def print(string="", string2=""):
        old_print(string, string2)
        logging.info(string)
        logging.info(string2)
print("OMG")
b = input()
print(a) ## Deliberate error for testing