How to duplicate sys.stdout to a log file?

Question

Edit: Since it appears that there\'s either no solution, or I\'m doing something so non-standard that nobody knows - I\'ll revise my question to also ask: What is the best w

Answer 1

I'm writing a script to run cmd-line scripts. ( Because in some cases, there just is no viable substitute for a Linux command -- such as the case of rsync. )

What I really wanted was to use the default python logging mechanism in every case where it was possible to do so, but to still capture any error when something went wrong that was unanticipated.

This code seems to do the trick. It may not be particularly elegant or efficient ( although it doesn't use string+=string, so at least it doesn't have that particular potential bottle- neck ). I'm posting it in case it gives someone else any useful ideas.

import logging
import os, sys
import datetime

# Get name of module, use as application name
try:
  ME=os.path.split(__file__)[-1].split('.')[0]
except:
  ME='pyExec_'

LOG_IDENTIFIER="uuu___( o O )___uuu "
LOG_IDR_LENGTH=len(LOG_IDENTIFIER)

class PyExec(object):

  # Use this to capture all possible error / output to log
  class SuperTee(object):
      # Original reference: http://mail.python.org/pipermail/python-list/2007-May/442737.html
      def __init__(self, name, mode):
          self.fl = open(name, mode)
          self.fl.write('\n')
          self.stdout = sys.stdout
          self.stdout.write('\n')
          self.stderr = sys.stderr

          sys.stdout = self
          sys.stderr = self

      def __del__(self):
          self.fl.write('\n')
          self.fl.flush()
          sys.stderr = self.stderr
          sys.stdout = self.stdout
          self.fl.close()

      def write(self, data):
          # If the data to write includes the log identifier prefix, then it is already formatted
          if data[0:LOG_IDR_LENGTH]==LOG_IDENTIFIER:
            self.fl.write("%s\n" % data[LOG_IDR_LENGTH:])
            self.stdout.write(data[LOG_IDR_LENGTH:])

          # Otherwise, we can give it a timestamp
          else:

            timestamp=str(datetime.datetime.now())
            if 'Traceback' == data[0:9]:
              data='%s: %s' % (timestamp, data)
              self.fl.write(data)
            else:
              self.fl.write(data)

            self.stdout.write(data)


  def __init__(self, aName, aCmd, logFileName='', outFileName=''):

    # Using name for 'logger' (context?), which is separate from the module or the function
    baseFormatter=logging.Formatter("%(asctime)s \t %(levelname)s \t %(name)s:%(module)s:%(lineno)d \t %(message)s")
    errorFormatter=logging.Formatter(LOG_IDENTIFIER + "%(asctime)s \t %(levelname)s \t %(name)s:%(module)s:%(lineno)d \t %(message)s")

    if logFileName:
      # open passed filename as append
      fl=logging.FileHandler("%s.log" % aName)
    else:
      # otherwise, use log filename as a one-time use file
      fl=logging.FileHandler("%s.log" % aName, 'w')

    fl.setLevel(logging.DEBUG)
    fl.setFormatter(baseFormatter)

    # This will capture stdout and CRITICAL and beyond errors

    if outFileName:
      teeFile=PyExec.SuperTee("%s_out.log" % aName)
    else:
      teeFile=PyExec.SuperTee("%s_out.log" % aName, 'w')

    fl_out=logging.StreamHandler( teeFile )
    fl_out.setLevel(logging.CRITICAL)
    fl_out.setFormatter(errorFormatter)

    # Set up logging
    self.log=logging.getLogger('pyExec_main')
    log=self.log

    log.addHandler(fl)
    log.addHandler(fl_out)

    print "Test print statement."

    log.setLevel(logging.DEBUG)

    log.info("Starting %s", ME)
    log.critical("Critical.")

    # Caught exception
    try:
      raise Exception('Exception test.')
    except Exception,e:
      log.exception(str(e))

    # Uncaught exception
    a=2/0


PyExec('test_pyExec',None)

Obviously, if you're not as subject to whimsy as I am, replace LOG_IDENTIFIER with another string that you're not like to ever see someone write to a log.