How to get an \"E\" output rather than 69?
package main
import \"fmt\"
func main() {
fmt.Print(\"HELLO\"[1])
}
Does Golang have funct
Interpreted string literals are character sequences between double quotes "" using the (possibly multi-byte) UTF-8 encoding of individual characters. In UTF-8, ASCII characters are single-byte corresponding to the first 128 Unicode characters. Strings behave like slices of bytes. A rune is an integer value identifying a Unicode code point. Therefore,
package main
import "fmt"
func main() {
fmt.Println(string("Hello"[1])) // ASCII only
fmt.Println(string([]rune("Hello, 世界")[1])) // UTF-8
fmt.Println(string([]rune("Hello, 世界")[8])) // UTF-8
}
Output:
e
e
界
Read:
Go Programming Language Specification section on Conversions.
The Go Blog: Strings, bytes, runes and characters in Go