How do I get the path and name of the file that is currently executing?

Question

I have scripts calling other script files but I need to get the filepath of the file that is currently running within the process.

For example, let\'s say I have th

Answer 1

Simplest way is:

in script_1.py:

import subprocess
subprocess.call(['python3',])

in script_2.py:

sys.argv[0]

P.S.: I've tried execfile, but since it reads script_2.py as a string, sys.argv[0] returned .