Distinct() with lambda?

Question

Right, so I have an enumerable and wish to get distinct values from it.

Using System.Linq, there\'s of course an extension method called Distinct<

Answer 1

You can use InlineComparer

public class InlineComparer : IEqualityComparer
{
    //private readonly Func equalsMethod;
    //private readonly Func getHashCodeMethod;
    public Func EqualsMethod { get; private set; }
    public Func GetHashCodeMethod { get; private set; }

    public InlineComparer(Func equals, Func hashCode)
    {
        if (equals == null) throw new ArgumentNullException("equals", "Equals parameter is required for all InlineComparer instances");
        EqualsMethod = equals;
        GetHashCodeMethod = hashCode;
    }

    public bool Equals(T x, T y)
    {
        return EqualsMethod(x, y);
    }

    public int GetHashCode(T obj)
    {
        if (GetHashCodeMethod == null) return obj.GetHashCode();
        return GetHashCodeMethod(obj);
    }
}

Usage sample:

  var comparer = new InlineComparer((i1, i2) => i1.PeticionEV == i2.PeticionEV && i1.Etiqueta == i2.Etiqueta, i => i.PeticionEV.GetHashCode() + i.Etiqueta.GetHashCode());
  var peticionesEV = listaLogs.Distinct(comparer).ToList();
  Assert.IsNotNull(peticionesEV);
  Assert.AreNotEqual(0, peticionesEV.Count);

Source: https://stackoverflow.com/a/5969691/206730
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