Passing an array as an argument to a function in C

Question

I wrote a function containing array as argument, and call it by passing value of array as follows.

void arraytest(int a[])
{
    // changed the array a
    a         


        

Answer 1

If you want to pass a single-dimension array as an argument in a function, you would have to declare a formal parameter in one of following three ways and all three declaration methods produce similar results because each tells the compiler that an integer pointer is going to be received.

int func(int arr[], ...){
    .
    .
    .
}

int func(int arr[SIZE], ...){
    .
    .
    .
}

int func(int* arr, ...){
    .
    .
    .
}

So, you are modifying the original values.

Thanks !!!