multiple prints on the same line in Python

Question

I want to run a script, which basically shows an output like this:

Installing XXX...               [DONE]

Currently, I print Installi

Answer 1

You should use backspace '\r' or ('\x08') char to go back on previous position in console output

Python 2+:

import time
import sys

def backspace(n):
    sys.stdout.write((b'\x08' * n).decode()) # use \x08 char to go back   

for i in range(101):                        # for 0 to 100
    s = str(i) + '%'                        # string for output
    sys.stdout.write(s)                     # just print
    sys.stdout.flush()                      # needed for flush when using \x08
    backspace(len(s))                       # back n chars    
    time.sleep(0.2)                         # sleep for 200ms

Python 3:

import time   

def backline():        
    print('\r', end='')                     # use '\r' to go back


for i in range(101):                        # for 0 to 100
    s = str(i) + '%'                        # string for output
    print(s, end='')                        # just print and flush
    backline()                              # back to the beginning of line    
    time.sleep(0.2)                         # sleep for 200ms

This code will count from 0% to 100% on one line. Final value will be:

> python test.py
100%

Additional info about flush in this case here: Why do python print statements that contain 'end=' arguments behave differently in while-loops?