a = [1,2,3,4,5]
b = [1,3,5,6]
c = a and b
print c
actual output: [1,3,5,6]
expected output: [1,3,5]
How can we ac
A functional way can be achieved using filter
and lambda
operator.
list1 = [1,2,3,4,5,6]
list2 = [2,4,6,9,10]
>>> list(filter(lambda x:x in list1, list2))
[2, 4, 6]
Edit: It filters out x that exists in both list1 and list, set difference can also be achieved using:
>>> list(filter(lambda x:x not in list1, list2))
[9,10]
Edit2: python3 filter
returns a filter object, encapsulating it with list
returns the output list.