std::enable_if to conditionally compile a member function

Question

I am trying to get a simple example to work to understand how to use std::enable_if. After I read this answer, I thought it shouldn\'t be too hard to come up wi

Answer 1

Here is my minimalist example, using a macro. Use double brackets enable_if((...)) when using more complex expressions.

template = 0>
using helper_enable_if = int;

#define enable_if(value) typename = helper_enable_if

struct Test
{
     template
     void run();
}