Dictionary style replace multiple items

Question

I have a large data.frame of character data that I want to convert based on what is commonly called a dictionary in other languages.

Currently I am going about it li

Answer 1

One of the most readable way to replace value in a string or a vector of string with a dictionary is stringr::str_replace_all, from the stringr package. The pattern needed by str_replace_all can be a dictionnary, e.g.,

# 1. Made your dictionnary
dictio_replace= c("AA"= "0101", 
                  "AC"= "0102",
                  "AG"= "0103") # short example of dictionnary.

 # 2. Replace all pattern, according to the dictionary-values (only a single vector of string, or a single string)
 foo$snp1 <- stringr::str_replace_all(string = foo$snp1,
                                      pattern= dictio_replace)  # we only use the 'pattern' option here: 'replacement' is useless since we provide a dictionnary.

Repeat step 2 with foo$snp2 & foo$snp3. If you have more vectors to transform it's a good idea to use another func', in order to replace values in each of the columns/vector in the dataframe without repeating yourself.