MongoDB: Is it possible to make a case-insensitive query?

Question

Example:

> db.stuff.save({\"foo\":\"bar\"});

> db.stuff.find({\"foo\":\"bar\"}).count();
1
> db.stuff.find({\"foo\":\"BAR\"}).count();
0
         


        

Answer 1

Using a filter works for me in C#.

string s = "searchTerm";
    var filter = Builders.Filter.Where(p => p.Title.ToLower().Contains(s.ToLower()));
                var listSorted = collection.Find(filter).ToList();
                var list = collection.Find(filter).ToList();

It may even use the index because I believe the methods are called after the return happens but I haven't tested this out yet.

This also avoids a problem of

var filter = Builders.Filter.Eq(p => p.Title.ToLower(), s.ToLower());

that mongodb will think p.Title.ToLower() is a property and won't map properly.