Retrieving the output of subprocess.call() [duplicate]

Answer 1

The following captures stdout and stderr of the process in a single variable. It is Python 2 and 3 compatible:

from subprocess import check_output, CalledProcessError, STDOUT

command = ["ls", "-l"]
try:
    output = check_output(command, stderr=STDOUT).decode()
    success = True 
except CalledProcessError as e:
    output = e.output.decode()
    success = False

If your command is a string rather than an array, prefix this with:

import shlex
command = shlex.split(command)