Arrow operator (->) usage in C

Question

I am reading a book called \"Teach Yourself C in 21 Days\" (I have already learned Java and C# so I am moving at a much faster pace). I was reading the chapter on pointers a

Answer 1

I had to make a small change to Jack's program to get it to run. After declaring the struct pointer pvar, point it to the address of var. I found this solution on page 242 of Stephen Kochan's Programming in C.

#include 

int main()
{
  struct foo
  {
    int x;
    float y;
  };

  struct foo var;
  struct foo* pvar;
  pvar = &var;

  var.x = 5;
  (&var)->y = 14.3;
  printf("%i - %.02f\n", var.x, (&var)->y);
  pvar->x = 6;
  pvar->y = 22.4;
  printf("%i - %.02f\n", pvar->x, pvar->y);
  return 0;
}

Run this in vim with the following command:

:!gcc -o var var.c && ./var

Will output:

5 - 14.30
6 - 22.40