Get the first item from an iterable that matches a condition

Question

I would like to get the first item from a list matching a condition. It\'s important that the resulting method not process the entire list, which could be quite large. For e

Answer 1

You could also use the argwhere function in Numpy. For example:

i) Find the first "l" in "helloworld":

import numpy as np
l = list("helloworld") # Create list
i = np.argwhere(np.array(l)=="l") # i = array([[2],[3],[8]])
index_of_first = i.min()

ii) Find first random number > 0.1

import numpy as np
r = np.random.rand(50) # Create random numbers
i = np.argwhere(r>0.1)
index_of_first = i.min()

iii) Find the last random number > 0.1

import numpy as np
r = np.random.rand(50) # Create random numbers
i = np.argwhere(r>0.1)
index_of_last = i.max()