Using AND with the apply function in Scheme

Question

Why doesn\'t the following work?

(apply and (list #t #t #f))

While the following works just fine.

(apply + (list 1 3 2))
         


        

Answer 1

If you REALLY wanted to have a function pointer to a function that does and, and you don't mind behavior different than the "real" and, then this would work:

(define and-l (lambda (a b) (and a b)))

Which you can apply like this:

(apply and-l (list #t #f))

The two caveats are:

1. All of the args get evaluated, in violation of the definition of and, which should have shortcutting behavior.
2. Only two arguments are allowed.