Get row where datetime column = today - SQL server noob

Question

In sql 2005, instead of building a query from dateparts year, month and date,

is there an more succinct way of writing the where clause?

Answer 1

On SQL Server 2008, you would have a new DATE data type, which you could use to achieve this:

SELECT (list of fields)
FROM dbo.YourTable
WHERE dateValue BETWEEN 
   CAST(GETDATE() AS DATE) AND DATEADD(DAY, 1, CAST(GETDATE() AS DATE))

The CAST(GETDATE() AS DATE) casts the current date and time to a date-only value, e.g. return '2010-04-06' for April 6, 2010. Adding one day to that basically selects all datetime values of today.

In SQL Server 2005, there's no easy way to do this - the most elegant solution I found here is using numeric manipulation of the DATETIME to achieve the same result:

SELECT (list of fields)
FROM dbo.YourTable
WHERE dateValue BETWEEN 
   CAST(FLOOR(CAST(GETDATE() AS FLOAT)) AS DATETIME) AND 
   DATEADD(DAY, 1, CAST(FLOOR(CAST(GETDATE() AS FLOAT)) AS DATETIME))