I am working with code that throws a lot of (for me at the moment) useless warnings using the warnings library. Reading (/scanning) the documentation I only found a way to d
Did you look at the suppress warnings section of the python docs?
If you are using code that you know will raise a warning, such as a deprecated function, but do not want to see the warning, then it is possible to suppress the warning using the catch_warnings context manager:
import warnings
def fxn():
warnings.warn("deprecated", DeprecationWarning)
with warnings.catch_warnings():
warnings.simplefilter("ignore")
fxn()
I don't condone it, but you could just suppress all warnings with this:
import warnings
warnings.filterwarnings("ignore")
Ex:
>>> import warnings
>>> def f():
... print('before')
... warnings.warn('you are warned!')
... print('after')
>>> f()
before
__main__:3: UserWarning: you are warned!
after
>>> warnings.filterwarnings("ignore")
>>> f()
before
after