lambda in for loop only takes last value [duplicate]

Answer 1

I know I am late, but I found a messy workaround which gets the job done (tested in Python 3.7)

If you use a double lambda (like I said, very messy) you can preserve the value, like so:

Step 1: Create the nested lambda statement:

send_param = lambda val: lambda: print(val)

Step 2: Use the lambda statement:

send_param(i)

The send_param method returns the inner most lambda (lambda: print(val)) without executing the statement, until you call the result of send_param which takes no arguments, for example:

a = send_param(i)
a()

Only the second line will execute the print statement.