How do I get a uint
unix timestamp in C++? I\'ve googled a bit and it seems that most methods are looking for more convoluted ways to represent time. Can\'t I j
I created a global define with more information:
#include
#include
#include
#define __FILENAME__ (__builtin_strrchr(__FILE__, '/') ? __builtin_strrchr(__FILE__, '/') + 1 : __FILE__) // only show filename and not it's path (less clutter)
#define INFO std::cout << std::put_time(std::localtime(&time_now), "%y-%m-%d %OH:%OM:%OS") << " [INFO] " << __FILENAME__ << "(" << __FUNCTION__ << ":" << __LINE__ << ") >> "
#define ERROR std::cout << std::put_time(std::localtime(&time_now), "%y-%m-%d %OH:%OM:%OS") << " [ERROR] " << __FILENAME__ << "(" << __FUNCTION__ << ":" << __LINE__ << ") >> "
static std::time_t time_now = std::time(nullptr);
Use it like this:
INFO << "Hello world" << std::endl;
ERROR << "Goodbye world" << std::endl;
Sample output:
16-06-23 21:33:19 [INFO] main.cpp(main:6) >> Hello world
16-06-23 21:33:19 [ERROR] main.cpp(main:7) >> Goodbye world
Put these lines in your header file. I find this very useful for debugging, etc.